Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. this method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. assume that the groups consist of 38 couples. complete parts (a) through (c) below. a. find the mean and the standard deviation for the numbers of girls in groups of 38 births.

a) Mean = 19

b) Standard Deviation = 3.08

Step-by-step explanation:

This is binomial probability distribution. We need to find the mean and standard deviation.

a) Mean

The formula for mean is:

Where n is the number of people, which is 38 and p is the probability of girl, which is 0.5

n = 38

p = 0.5

So,

Mean = 19

b) Standard Deviation

Standard deviation has the formula:

Where n and p are the same variables in part (a)

So we plug them in and find:

Standard Deviation = 3.08

step-by-step explanation: yes

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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