Suppose that salaries for recent graduates of one university have a mean of $25,500 with a standard deviation of $1050. using chebyshev's theorem, what is the minimum percentage of recent graduates who have salaries between $22,350 and $28,650? round your answer to one decimal place.

88.9%

Step-by-step explanation:

Given:

Mean salary for the graduates = $25,500

Standard deviation = $1050

Minimum salary = $22,350

Maximum salary = $28,650

Now,

Using Chebyshev's Theorem

Percentage =  ................(1)

here,

The value of 'k' is calculated as:

k =

on substituting the values, we get

k =  

or

k = 3

on substituting the value of k in (1), we get

Percentage =

or

Percentage =

or

Percentage = 88.9%

-232

step-by-step explanation:

i think the correct option is the second option.