2(3x + 8) = 2x +16 + 4x one solution, infinetly many solution, no solution?

Simplifying
2(3x + 8) = 2x + 16 + 4x

Reorder the terms:
2(8 + 3x) = 2x + 16 + 4x
(8 * 2 + 3x * 2) = 2x + 16 + 4x
(16 + 6x) = 2x + 16 + 4x

Reorder the terms:
16 + 6x = 16 + 2x + 4x

Combine like terms: 2x + 4x = 6x
16 + 6x = 16 + 6x

Add '-16' to each side of the equation.
16 + -16 + 6x = 16 + -16 + 6x

Combine like terms: 16 + -16 = 0
0 + 6x = 16 + -16 + 6x
6x = 16 + -16 + 6x

Combine like terms: 16 + -16 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

hope this helps :)

Just a question- could you organize the data better? i just cannot tell which number are for which bakery. i will be happy to answer this question if you could do this for me! : )