What is an equation of the line that is parallel to y=3x−8 and passes through (1, 8) ?

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The final answer is 3x3+6x2+8x+24+47x−2mark me brainliest

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.

given that    bisects ∠dbc, which statement must be true? the answer is:   m∠abd = m∠abc 

This is impossible to answer without the graph from the if you post the graph then we can .