Two baseball teams are tied for first place at the end of the season. according to tiebreaking rules, one of the teams will be designated as "team x" and the other as "team y." team x will then choose between two scenarios.

scenario 1: the tied teams will play two games in team x's ballpark. team x must win both games to be declared the champion. otherwise, team y is the champion.

scenario 2: the tied teams will play one game in team y's ballpark. the winner of this game will be declared the champion.
(refer to tiebreaking scenarios 1 and 2.)

let px and py be the respective probabilities of team x and team y winning in their own ballparks. if py = 0.7, which inequality describes the values of px that would make scenario 1 the more favorable choice for team x?

a. 0.35 < pₓ ≤ 1


b. 0.49< pₓ ≤ 1


c. √0.3< pₓ ≤ 1


d. √0.7 < pₓ ≤ 1

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w

where is the graph

step-by-step explanation:

the furthest the dog can be is 508 meters away from the house, and the closest he can be is 492 meters away from the house.