The volume of a room is 400 cu. m and its height is 25 m. find the cost of carpeting the floor of the room at 5 paisa per sq. cm.

Step-by-step explanation:

This only works if the room is a prism shaped, or cylinder.  

Volume of a prism or cylinder is area of he base times height.  So since we know the height and volume we can fand the area.

V = h*B

B = V/h

B = 400/25

B = 8

This is a very narrow room, anyway, the area of the base, which we want to carpet is 8 square meters. Can you figure out how much it will cost since each square meter will cost 5?

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°