Consider the sets a={n e p: n is odd} b = {n e p: n is prime) c = {4n +3: n € p} d = {x e r : x2 - 8x + 15 = 0} which of these sets are subsets of which? consider all 16 possibilities.

,, and .

Step-by-step explanation:

The given sets are

A={n ∈ P:n is odd}

B = {n ∈ P:n is prime)

C = {4n +3:n ∈ P}

D = {x ∈ R : x² - 8x + 15 = 0}

P is the set of prime numbers and R is the set of real numbers.

So, the elements of all sets are

A = {3, 5, 7, 11, 13, 17, 19, 23, ...}

B = {2, 3, 5 , 7, 11, 13, 17, 19, 23, ...}

C = {11, 15, 23, ...}

D = {3,5}

Each sets is a subset of it self. So,

All the elements of A lie in set B, so A is a subset of B.

Since and , So, C is not the subset of A and B.

D has two elements, 3 and 5, Since and , therefore

and

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !