A3ml unit dose of levalbuterol hcl contains 0.63mg of active ingredient. if 2 unit doses are used, how many mg of active ingredient are used?

 0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl =

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: