How do i do this problem show work

which of the following equations has only one solution? a. x^2 + 4x + 4 = 0 b. x^2 + x = 0 c. x^2 - 1 = 0

Answer

A. is the answer

Step-by-step explanation:

Determine the number of solutions using the discriminant D=b^2-4 ac

D=4^-4 x 1 x 4

simplify the expression

D= 4^2-4 x 1 x 4

which is

D=0

since D=0, the quadratic equation has 1 real solution

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )