In a small private school, five students are randomly selected from eighteen available students. what is the probability that they are the five youngest students?

1 / 8568

Step-by-step explanation:

The number of combinations is:

₁₈C₅ = (18! / (5! (18−5)!)

₁₈C₅ = 8568

There are 8568 possible groups of 5 that can be selected from 18.  Only 1 of those groups contains the five youngest students.  So the probability is:

P = 1 / 8568 ≈ 0.0117%

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

4th option is correct xy=-10

if this was to u plzz mark me the brainliest