Aproton and an antiproton collide in a particle accelerator and convert their masses into energy. how much energy is produced if the mass of each particle is 1.9x10-27 kg?

34.2 × 10⁻¹¹ J

Step-by-step explanation:

Data provided in the question:

A proton and an antiproton collide

Mass of proton = 1.9 × 10⁻²⁷ kg

Mass of antiproton = 1.9 × 10⁻²⁷ kg

Now,

By Einstein Theory,

The Energy is given as:

E = mc²

Where,

E is the energy

m is the mass

c is the speed of the light = 3 × 10⁸ m/s

Therefore,

The total energy produced = Energy by proton + Energy by antiproton

or

The total energy produced

= 1.9 × 10⁻²⁷ × ( 3 × 10⁸ )² + 1.9 × 10⁻²⁷ × ( 3 × 10⁸ )²

or

= 2 × 1.9 × 10⁻²⁷ × ( 3 × 10⁸ )²

= 3.8 × 10⁻²⁷ × 9 × 10¹⁶

= 34.2 × 10⁻¹¹ J

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol