Find three consecutive integers whose sum is equal to −354. three consecutive integers in ascending form are

-119, -120, and -121

Step-by-step explanation: This problem states that the sum of three consecutive integers is -354 and it asks us to find the integers. Three consecutive integers can be represented as followed.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

Since the sum of our three consecutive integers is -354, we can set up an equation to represent this.

X + X + 1 + X + 2 = -354

Now, we can simplify on the left side of the equation.

3x + 3 = -354

      -3      -3    ← subtract 3 on both sides of the equation

3x = -357

÷3     ÷3     ← divide both sides by 3

X = -119

X ⇒ first integer = -119

X + 1 ⇒ second integer = -120

X + 2 ⇒ third integer = -121

Therefore, our three consecutive integers are -119, -120, and -121.

First divide -354 by 3 and you will get -118

answer

-118

-119

-117

DONT FORGET MINUS SIGN BEFORE THE ANSWERS!!!:D

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752