Ali uses 3/8 of a 2-pound bag of clay to make a set of bowls. each set has 4 bowls. which expression is the correct way to answer the questions

how many pounds of clay does ali use for a set of bowls

and

how many pounds of clay are used for each bowl

answers choices:
2•3/8
2•3/8 divided by 4
2•4 divided by 3/8
3/8 divided by 2
2 divided by 3/8
2+3/8

For this case we have to if Ali uses of 2 pounds of clay for a game of 4 bowls we have:

Thus, Ali uses pounds of clay to make a game.

If we want to know how many pounds of clay are used in each bowl, we must divide the previous result by 4, that is:

Part A:

Part B:

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

the f

last graph i believe

step-by-step explanation:

worked it out i believe