Jorge invested $28,000 into two accounts. the amount he put in his money market account was $2,000 less than twice what he put into a cd.

$10,000 invested in CD

$18,000 invested in money market

Step-by-step explanation:

Complete Question:

Jorge invested $28,000 into two accounts. The amount he put in his money market account was $2,000 less than twice what he put into a CD. How much did he invest in each account?

Let money put in CD be x

So

Money put in money market will be  2x - 2000

Alltogether, that is 28,000. Thus, we can write:

x + (2x-2000) = 28,000

Solving, we get:

x + (2x-2000) = 28,000

x + 2x - 2000 = 28,000

3x = 30,000

x = 30,000/3 = 10,000

$10,000 invested in CD

We know 2x - 2000 invested in money market, so:

2(10,000) - 2000 = $18,000 invested in money market

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.