Find the zeros of the function and 2x² + 72=0

x = ± 6i

Step-by-step explanation:

Given

2x² + 72 = 0 ( subtract 72 from both sides )

2x² = - 72 ( divide both sides by 2 )

x² = - 36 ( take the square root of both sides )

x = ±

  = ±( )

  = ±( × ) → = i

  = ± 6i