Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?
f(x) = (x + 3)2 + 3
f(x) = (x + 3)2 − 6
f(x) = (x + 6)2 + 3
f(x) = (x + 6)2 − 6

Complete the square
move the 3 aside and work in parenthasees
f(x)=(x^2+6x)+3
take 1/2 of 6 and square it (6/2=3, 3^2=9)
add 9 and -9 inside
f(x)=(x^2+6x+9-9)+3
factor perfect square
f(x)=((x+3)^2-9)+3
get rid of parenthases
f(x)=(x+3)^2-9+3
f(x)=(x+3)^2-6

2nd choice

221,500 is the answer