Find the value of k if it is known that the line y=kx+2 goes through point:

p (−7, 12)

c(3, −7)

k = -10/7 and k = -3

Step-by-step explanation:

Given: y = kx + 2

where k is the slope of line and 2 is y-intercept.

∵ line y = kx + 2 is passing through point P (-7, 12), ∴ x = -7 and y = 12

Now substituting the value of x and y in above equation,

y = kx + 2

12 = k(-7) + 2

-7k = 12 - 2

- 7k = 10

In the same way, ∵ line y = kx + 2 is passing through point P (3, -7), ∴ x = 3 and y = -7

y = kx + 2

Now substituting the value of x and y in above equation,

-7 = k(3) + 2

3k = -7 - 2

3k = - 9

k = -3

-2 is the right

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)