The graph shows the relationship between the width y and the length x of a rectangle in inches. the perimeter of a second rectangle is 10 inches less than the perimeter of the first rectangle. a. decribe the graph of the relationship between the width and the length of the second rectangle. the graph is a line segment connecting open circles at (0,10) ( 0 , 10 ) and (10,0) ( 10 , 0 ) . the graph is a line segment connecting open circles at (0,15) ( 0 , 15 ) and (15,0) ( 15 , 0 ) . the graph is a line segment connecting open circles at (0,25) ( 0 , 25 ) and (25,0) ( 25 , 0 ) . the graph is a line segment connecting open circles at (0,30) ( 0 , 30 ) and (30,0) ( 30 , 0 ) . question 2 b. how does the graph in part (a) compare to the graph shown? the slope of the graph of the second rectangle has a slope that is the slope of the graph shown. the x x - and y y -intercepts of the graph are the origin than the intercepts in the graph shown.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

multiple all that

step-by-step explanation:

27×17

answer: - (a)

(b) 88 seats

step-by-step explanation:

given: in an auditorium, there are 22 seats in the first row and 28 seats in the second row.

thus first term=

second term=

the number of seats in a row continues to increase by 6 with each additional row.

⇒d= 6

a) given formula :

b)   let the number of seats (n) = 12

substitute n=12 in the explicit rule formed in (a)

∴there are 88 seats in 12 rows.

that one look

step-by-step explanation: