At the north campus of a performing arts school, 30% of the students are music majors. at the south campus, 70% of the students are music majors. the campuses are merged into one east campus. if 46% of the 1000 students at the east campus are music majors, how many students did the north and south campuses have before the merger?

The north campus had 600 students (180 music majors)

The south campus had 400 students (280 music majors)

Step-by-step explanation:

x = number of students at the north campus before the merger

If the total of students for the two school is given as 1000, so:

(1000 - x) =  number of students at the south campus before the merger.

The equation for music major is:

0,3x + 0,7(1000-x) = 0,46(1000)

0,3x + 700 - 0,7x = 460

0,3x - 0,7x = 460 - 700

- 0,4x = -240

x = -240/-0,4

x = 600 > total number of students at the north campus

600*(0,3) = 180 music majors at the north

100 - 600 = 400 > total number of students at the south campus

400*(0,7) = 280>music majors at the south

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.