Aprojectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. the range (the total distance traveled by the projectile over level ground) of the projectile is approximated by the equation . find the launch angle of a projectile with an initial speed of 85ft/s and a range of 170 ft.

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation , where we will use ft for distances.

From the given equation we have then , which means since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and  v = 85 ft/s, we can substitute these values from the equation written, and we will have , and from now on we have just to use a calculator, obtaining

17

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b