Triangle a b c is cut by line segment m n. line segment m n goes from side a b to side b c. the length of m n is 9 feet. the lengths of b m and m a are 4 feet. the lengths of b n and n c are 3 feet. what is the length of line segment a c? 3 ft 4 ft 9 ft 18 ft

The length of AC is 18 feet ⇒ 4th answer

Step-by-step explanation:

* Lets revise an important theorem for a triangle

- If a line segment joining the mid-points of two sides of a triangle,

  then this line segment is parallel to the third side of the triangle and

  equal half its length

* Lets use this theorem to solve the problem

- In Δ ABC

∵ Line MN intersects the sides AB at M

∵ MA = MB

∴ M is the mid point of the side AB

∵ Line MN intersects the sides BC at N

∵ NC = NB

∴ N is the mid point of the side BC

- By using the theorem above

  In Δ ABC

∵ M is the mid-point of AB

∵ N is the mid-point of BC

∴ MN // AC

∴ MN = AC

∵ The length of MN = 9 feet

∵ MN = AC

∴ 9 = AC

- Multiply both sides by 2

∴ AC = 18 feet

* The length of AC is 18 feet

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.