Write the virtud for a parabola that satisfies the condition given. then write the equation in the form y=ax^2+bc+c. vertex (3,1) and a=3 write the equation in the form y=ax^2+bx+c

Step-by-step explanation:

For vertex (h, k) and vertical scale factor "a", the vertex form of the equation of a parabola is ...

  y = a(x -h)^2 +k

For (h, k) = (3, 1) and a = 3, the equation in vertex form is ...

  y = 3(x -3)^2 +1

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Expanding this gives the equation in standard form.

  y = 3(x^2 -6x +9) +1

  y = 3x^2 -18x +28

idk

step-by-step explanation: i just don't