Consider a multiple choice exam with 10 questions, and with 4 possible answers to each question (labeled a, b, c, and d). 1a. what is the probability of getting a perfect score just by guessing? 1b. what is the probability of getting at least one question correct, just by guessing? explain your thought process briefly. 2. each ruid is 9-digits long, but the 4th and 5th digits must both be 0. how many different ruids can there be?

(1a) 9.54e-07 (1b) 0.9437 (2)

Step-by-step explanation:

We have n = 10 questions. For each question in the multiple choice exam, we can choose the correct answer with probability p = 0.25 or an incorrect answer with probability q = 0.75 (just by guessing). Besides is reasonable to believe that questions are independent. Let X be the random variable that represents the number of correct answers (just by guessing) observed during the n = 10 questions, so, X have a binomial distribution.

(a) The probability of getting a perfect score just by guessing is

(b) The probability of getting at least one question correct, just by guessing

2. Each RUID is 9-digits long, there are 10 digits, each of the nine positions for a digit of the RUID has 10 posibilities except the 4th and 5th positions which must be both 0. For the multiplication rule there can be different RUIDS.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: