Two cars, p and q, travel with the same constant velocity 15 m/s along a straight level road. the front car p is 24 m behind the rear of the car q. at a given instant both cars decelerate, p at 4 m/s/s and q at 5 m/s/s. find, in terms of t, the distance between the cars t seconds later.

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

fjfjfhdhdhdhjjdjdjdjdjjd thats the answers

step-by-step explanation:

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x