For this problem, involving a weighted die, assume that the outcomes 1 through 4 are equally likely, that the outcomes 5 through 6 are equally likely, and that outcome 1 is 3 times as likely as outcome 5.

(1) what probability should be assigned to rolling a 4?

(2) what probability should be assigned to rolling a 6?

a.

b.

Step-by-step explanation:

We are given that a die is rolled

Let x bet the cases in favor of 5.

Number of cases in favor of 6=x

Then according to question

Number of cases in favor of  1=3x

Number of cases in favor of 2=3x

Number of cases in favor of 3=3x

Number of cases in favor of 4=3x

Sum of total cases=

Probability of getting 5 =

Probability of getting 1=

1.We have to find probability should be assigned to rolling a 4.

The probability of getting =

2.We have to find the probability of rolling 6.

The probability of getting 6=

after simplifying it i got: -36.25 as my answer. hope that !

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length