Mathematics, 08.10.2019 05:30 hosfordkenya4

Suppose that an insurance company classifies people into one of three classes —good risks, average risks, and bad risks. their records indicate that the probabilitiesthat good, average, and bad risk persons will be involved in an accident over a1-year span are, respectively, .05, .15, and .30.
a. if 20 percent of the populationare "good risks," 50 percent are "average risks," and 30 percent are "bad risks,"what proportion of people have accidents in a fixed year?
b. if policy holder a hadno accidents in 1987, what is the probability that he or she is a good (average)risk?

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Answer from: dasdsadsafdhgifsdu

a. 17.5 %

b. 0.2303

Step-by-step explanation:

Let's start defining the conditional probability :

Suppose two events A and B where P(A)0 and P(B)0

and P(A ∩ B) = P(A,B) where (A ∩ B) is the event where A and B occur both at the same time.

The conditional probability :

$P(A/B)=\frac{P(A,B)}{P(B)} \\P(B/A)=\frac{P(A,B)}{P(A)}$

Let's define the following events :

A : ''Randomly chosen person had accident in a fixed year''

GR : ''The person belongs to good risks classification''

AR : ''The person belongs to average risks classification''

BR : ''The person belongs to bad risks classification''

The information given is :

$P(GR)=0.20\\P(AR)=0.50\\P(BR)=0.30$

$P(A/GR)=0.05\\P(A/AR)=0.15\\P(A/BR)=0.30$

We need to calculate P(A)

$P(A)=P(A,GR)+P(A,AR)+P(A,BR)\\P(A)=P(A/GR).P(GR)+P(A/AR).P(AR)+P(A/BR).P(BR)\\P(A)=(0.05)(0.2)+(0.15)(0.5)+(0.30)(0.30)\\P(A)=0.175$

Then 17.5% of people have accidents in a fixed year

b. If U is an event ⇒

$P(U)=1-P(U^{c})$

Where $U^{c}$ is the event where U does not occur

We need to calculate :

$P(GR/A^{c})$

$P(A^{c})=1-P(A)=1-0.175\\P(A^{c})=0.825$

$P(A^{c}/GR)=1-P(A/GR)=1-0.05\\P(A^{c}/GR)=0.95$

$P(A^{c}/GR)=\frac{P(A^{c},GR)}{P(GR)} \\0.95=\frac{P(A^{c},GR)}{0.2} \\P(A^{c},GR)=(0.95)(0.2) \\P(A^{c},GR)=0.19$

$P(GR/A^{c})=\frac{P(GR,A^{c})}{P(A^{c})}=\frac{0.19}{0.825}\\P(GR/A^{c})=0.2303$

Answer from: Quest

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

Brainliest and 75 points for whoever can explain how to get these given: △acm, m∠c=90°, cp⊥ am. ap=

Answer from: Quest

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

ask for details followreport by buttfacelily 2 minutes ago

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