What is the vertex of the quadratic function? f(x)= (x-8)(x-4)

C

Step-by-step explanation:

The vertex lies on the axis of symmetry which is located at the midpoint of the zeros.

Given

f(x) = (x - 8)(x - 4)

To find the zeros let f(x) = 0, that is

(x - 8)(x - 4) = 0

Equate each factor to zero and solve for x

x - 8 = 0 ⇒ x = 8

x - 4 = 0 ⇒ x = 4

Thus

= = = 6

Substitute x = 6 into f(x) for corresponding y- coordinate of vertex

f(6) = (6 - 8)(6 - 4) = (- 2)(2) = - 4

Vertex = (6, - 4 ) → C

yes

yes yes yes

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic