Distance and midpoint mini-project

the grid shows the locations of a sandbox and a fountain

in a park. each grid square represents one square meter.

1. which formula would be used to calculate the distance

between the sandbox and the fountain? (1 point)

a. y2 - 3

b. *, - x,? + 92-y,

x2 - x

(x + x2 + y2 )

d. a? + b2 = c?

2

step-by-step explanation:

x = 3 ± √(5+y)

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

b. hannah is playing with her cousin at