Abag of 29 tulip bulbs contains 10 red tulip bulbs, 12 yellow tulip bulbs, and 7 purple tulip bulbs. (a) what is the probability that two randomly selected tulip bulbs are both red? (b) what is the probability that the first bulb selected is red and the second yellow? (c) what is the probability that the first bulb selected is yellow and the second red? (d) what is the probability that one bulb is red and the other yellow?

Answer

given,

A bag consist of 29 tulip bulbs

a) P(both bulb are red ) =

     =

     =

     = 0.111

P(both bulb are red ) = 0.111

b) P(first bulb is red and second yellow ) =

     =

     =

     = 0.148  

P(first bulb is red and second yellow ) = 0.148

c) P(first bulb is yellow and second red ) =

     =

     =

     =0.148

P(first bulb is yellow and second red ) = 0.148

d) P(one bulb is red and the other yellow) =

     = P(first bulb is yellow and second red ) + P(first bulb is red and second yellow )

     = 0.148 + 0.148

     = 0.296

P(one bulb is red and the other yellow) = 0.296

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

it is x=-4

step-by-step explanation: