Acarpentry shop currently sells 66000 decoy ducks per year at a cost of 16 dollars each. in the previous year when they raised the price to 21 dollars, they only sold 51000 decoy ducks that year. assuming the amount of decoy ducks sold is in a linear relationship with the cost, what price should the carpentry shop charge per decoy duck to maximize their revenue?

19 dollars

Step-by-step explanation:

First we have to find the line that goes trough the two points. And it has the form :

m is often called the slope.

Given the two points (66000, 16) and (51000, 21) we find m with this formula:

We pick the point (51000,21) and plug it into the equation of the line and we find b:

Where x represents the quantity and y represents the price.

The revenue is price times quantity, since price is y and quantity is x, we get

So the quantity that maximizes revenue is 57000,

a

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.