Two fair dice are tossed, and the up face on each die is recorded. find the probability of observing a: { a 3 appears on each of two dice.} use 4 significant decimal places for your answer, and use the proper rules of rounding. i am looking for just the answer, not the equation.

0.0278

Step-by-step explanation:

On a fair dice , there are six numbers (1,2,3,4,5,6) written on each face of dice.

Thus, when we thrown two dice , the sample space for the possibilities of outcomes will become :

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

i.e. Total number of outcomes = 36

For event A: { 3 appears on each of two dice.}

The favorable outcome = (3,3)

Now, the required probability :

Hence, the required probability is 0.0278.

use google you idiot omg you're so annoying

step-by-step explanation: