Apicture is 4.25 inches wide and 7.75 inches tall. it is mounted in a frame with a border of x inches wide on all sides. if the area of the shaded border is 45 inches squared, what is its width x?

ANSWER:  

Width of border is 1.5 inches            

SOLUTION:

Given,  

Width of the photo graph = 4.25 inches

Height of the photo graph = 7.75 inches  

And it is mounted in a frame with border of x inches, so the dimensions after mounting will be

Width after mounting = (4.25 + x + x) [ since, two sides of photograph will have borders

Height after mounting = (7.75 + x + x) [ since, two sides of photograph will have borders  

Area of border = 45 square inches

As we all know that, photograph will be in rectangular shape,  

Area of photograph =

Area of photograph after mounting =

Now, area of border = Area of photograph after mounting - Area of photograph before mounting

  [by dividing the equation with 4]

As length can’t be negative, x =

Hence , the width x is 1.5 inches

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

.bjbjk.b,j.l.

step-by-step explanation: