To show that the set of all real numbers between 0 and 1 had a higher cardinality than n_0, we assumed first that they had the *same* cardinality. then we showed that there was at least one number which was not counted in the list. suppose now that we *only* consider those numbers between 0 and 1 which have a decimal expansion consisting of 0’s and 1’s. (e. g. 0.10101…, 0. etc.) show that this set *also* has a cardinality greater than n_0 (once again by the same kind of construction).

i really dont know

step-by-step explanation:

not only in mathematics, scientific proof also are required in the other field of science. also maths proofs are of particular structure, containing steps and logics. so proving is like doing science, it is science. that's why it is important to prove. 

an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: