When a computer disk manufacturer tests a disk, it writes to the disk and then tests it using a certifier. the certifier counts the number of missing pulses or errors. the number of errors on a test area on a disk has a poisson distribution with = 0.2. (a) what is the expected number of errors per test area? (b) what percentage of test areas have two or fewer errors?

Step-by-step explanation:

Let X be the random variable representing the number of missing pulses or errors.  The number of errors on a test area has Poisson with parameter = 0.2

a) Expected no of errors per test area =

(Since in a Poisson distribution mean = parameter value)

b)percentage of test areas have two or fewer errors

100*P(X≤2)

Hence percentage = 99.885%

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions