Derive a partial differential equation describing the evolution of the concentration b(x, t) of a population of bacteria along a water filament. assume that the bacteria reproduce locally at a rate proportional to their concentration, with proportionality constant λ, and that they diffuse with a flux proportional to −bx, with proportionality constant µ. in order to derive the equation, start with an integral principle describing

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

because i took test

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.