Find the value of c so that (x+3) is a factor of the polynomial p(x)

p(x)=x^3-4x^2+cx+33

c=?

we know that x + 3 is a factor of the polynomial, that means that if we divide the polynomial by (x + 3), we'll get a remainder of 0.

likewise by the remainder theorem, since that x + 3 = 0, or x = -3, if we plug that -3 as the argument for p(x), namely p(-3), our output will be zero, if indeed (x + 3) is a factor of that polynomial, so then, let's plug that -3 in p(x).

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.