Tara's house is 50 feet long, her bike is 4 feet long, and tara is 4 feet,9 inches .combined, tara, her house and her bike are still 10 feet shorter than the largest salami. how long was the largest salami?

The length of the largest salami is 48.75 feet

Solution:

Given,  

Tara’s house = 50 feet

Tara’s bike = 4 feet

Tara’s height = 4 feet 9 inches  

We know 12 inch = 1 foot

9 inch = foot = 0.75 foot

4 feet 9 inch = 4 feet +0.75 feet = 4.75 feet

Adding tara’s (house + bike + height) = 50+4+4.75 = 58.75

It is given that that combining tara’s house, bike and height  are 10 feet shorter than the largest salami which means difference between Tara’s(house + bike + height)  and largest salami  is 10.

Tara’s(house + bike + height) - largest salami   = 10

58.75 - largest salami = 10

58.75-10=largest salami

48.75 = largest salami.

The largest salami is 48.75 feet long

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.