On a coordinate plane, a line goes through (0, negative 4) and (12, 6). a point is at (12, negative 2). what is the equation of the line that is parallel to the given line and passes through the point (12, −2)? y = –six-fifths x + 10 y = –six-fifths x + 12 y = –five-sixths x – 10 y = five-sixths x – 12

y = Five-sixths x – 12

Step-by-step explanation:

Given that the line goes through points (0,-4) and (12,6) then the slope of the line can be calculated as;

m=rise/run

m=6--4/12-0  = 10/12 = 5/6

A line that is parallel to this line will have a slope of 5/6.

If it passes through point (12,-2) then the equation will be;

Points (12,-2) , (x,y) , m=5/6

y--2/x-12 = 5/6

y+2/x-12 =5/6perform cross multiplication

6(y+2) = 5(x-12)

6y+12=5x-60collect like terms

6y=5x-60-12

6y=5x-72

y= 5/6x -12

it 2

step-by-step explanation:

8^1/3=2

6mm^3 or .6cm^3

      216

      /   \

  36     6

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6     6   6

factor trees are nice.