In a shipment of 56 vials, only 13 do not have hairline cracks. if you randomly select 3 vials from the shipment, in how many ways can at least one of the 3 selected vials have a hairline crack if the order of selection does not matter?

27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

Hence, the required number of ways =27434

yes

step-by-step explanation:

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )