Abag contains 5 blue marbles, 6 red marbles, and 9 green marbles. two
marbles are drawn at random, one at a time. what is the probability of
selecting a green marble and then, without replacing it, a red marble?

9/76

Step-by-step explanation:

9/20*5/19=9/76

27/190 or 14.21%

Step-by-step explanation:

Probability is how likely an event could occur if the given condition is true.

Probability = no. of favourable outcomes /total no. of outcomes

First calculate the probability of green marble

Probability of getting a green marble = 9 / (5+ 6+9) = 9 / 20

Probability of getting a red marble  = 6 / (20-1) = 6 / 19

Probability of getting a green marble before red = (9/20) x (6/19)

Probability of getting a green marble before red = (9/20) x (6/19) = 54/380 = 27/190 = 14.21%

i need the options

step-by-step explanation: