The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 cm in each. use differentials to estimate the maximum error in the calculated area of the rectangle.

The maximum error in the calculated area of the rectangle is

Step-by-step explanation:

The area of a rectangle with length and width is so the differential of A is

so

We know that each error is at most 0.1 cm, we have , . To find the maximum error in the calculated area of the rectangle we take , and , . This gives

Thus the maximum error in the calculated area of the rectangle is

no he doesnt because "-16' is negatiive

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form