Without solving the equation, determine the nature of the roots of 2x2 + 3x + 9 = 0.
two, real unequal roots
two, real equal roots
no real roots

No real roots

Step-by-step explanation:

2x² + 3x + 9 = 0

the discriminant for this quadratic equation is given by

b²-4ac

in this case, a = 2, b = 3 and c=9

hence b²-4ac

= 3² - 4(2)(9)

= 9 - 72

= -63

Recall that if the discriminant of a quadratic function is negative, then the function has no real roots.

hence in this case, there are no real roots

b. x + 1

step-by-step explanation:

i'am smart

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation: