Solve for x.
a. x + 5 = 6/x
b. x = 24/x - 5
c. x = 1/x

a. For equation value of x are 1 and -6.

b. For equation value of x are 3 and -8

c. For equation value of x are -1 and 1.

Solution:

a)Given equation is

On cross multiplying we get,

x(x+5)=6

On splitting the middle term we get,

When x - 1 = 0 , x = 1

When x + 6 = 0 , x = -6

So two values of x which satisfies the given equation are 1 and -6.

b)Given equation is

On splitting the middle term we get

When x - 3 = 0 , x = 3

When x + 8 = 0 , x = -8

So two values of x which satisfies the given equation are 3 and -8.

c) Given equation is

Using algebraic identity   we get

=(x-1)(x+1)=0

When x - 1 = 0 , x =1

When x + 1 = 0 , x = -1

So two values of x which satisfies the given equation are 1 and -1.  

answer: options?

step-by-step explanation:

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x