The admission fee at a water park is $16.00 for children and $27.25 for adults on a certain day 295people entered the park and the admission fees collected totaled $6,126.25how many children and how many adults were admitted

Let a = adult

Let c = children

a + c = 295

27.25a + 16.00c = 6126.25

We have two equations in two unknowns.

Take it from here.

ANSWER:

170 children and 125 adults visited the park.

SOLUTION:

Given, the admission fee at a water park is $16.00 for children and $27.25 for adults

On a certain day 295 people entered the park and the admission fees collected totaled $6,126.25.

We need to find how many children and how many adults visited the park.

Let the number of children be x and the number of adults be y

And total fee collected is $6,126,25

Total fee collected for children + total fee collected for adults = $6,126.25

16x + 27.25y = 6126.25 --- eqn (1)

Then, total attended people are 295

x + y = 295 --- eqn (2)

y = 295 – x

Substitute y value in (1)

16x + 27.25(295 – x) = 6126.25

16x - 27.25x + 27.25 × 295 = 6126.25

-11.25x + 8038.75 = 6126.25

11.25x = 8038.75 – 6126.25

11.25x = 1912.50

x =

x = 170

Now, put x value in (2)

170 + y = 295

y = 295 – 170

y = 125.

Hence, 170 children and 125 adults visited the park.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.