During the period of time that a local university takes phone-in registrations, calls come in at the rate of one every two minutes. what is the expected number of calls in one hour? what is the probability of three calls in five minutes (to 4 decimals)? what is the probability of no calls in a five-minute period (to 4 decimals)?

The expected number of calls in one hour is 30.

The probability of three calls in five minutes is

The probability of no calls in a five-minutes is

Step-by-step explanation:

We know that the calls come in at the rate of one every two minutes. To find the expected number of calls in one hour you need to:

To find the probability of these events:

three calls in five minutesno calls in a five-minutes

We are going to use the Poisson distribution because is used when it is desirable to determine the probability of obtaining x occurrences over an interval of time like in this situation.

The Poisson probability function is defined by

where

x = 0, 1, 2, 3 ...

e = 2.71828

μ = mean number of successes in the given time interval or region of space

To find the probability of three calls in five minutes you need to:

Find μ

Evaluate the formula for k = 3 and μ = 2.5

To find the probability of no calls in a five-minute period you need to:

Evaluate the formula for  k = 0 and μ = 2.5

56 ur welcome:

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!