Perpendicular to the line y=1/2x-8; passes through (7,-6). write the slope-intercept form of the equation.

ANSWER:

The slope intercept form of the required line is y = -2x + 20.

SOLUTION:

Given, line equation is

And, Perpendicular line to the given line  passes through (7,-6).  

We need to find the slope intercept form of perpendicular line of given line.  

We already have the point (7, -6) but we need to find the slope.

Now, we know that, product of slopes of two perpendicular lines equals to -1.

Slope of given line is , by comparing with the general form of slope intercept form.

slope of required line = -1

Slope of perpendicular line = -2

Now, line equation of perpendicular line in point slope form is

y – (-6) = -2(x – 7)

y + 6 = -2x + 14

y = -2x + 20

the above equation is in the form of slope intercept form of a line equation  

where slope m = -2 and intercept c = 20

hence, the slope intercept form of the required line is y = -2x + 20.

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step-by-step explanation:

basically 2/5.

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