The number of surface flaws in plastic panels used in the interior of automobiles has a poisson distribution with a mean of 0.06 flaws per square foot of plastic panel. assume an automobile interior contains 10 square feet of plastic panel. (a) what is the probability that there are no surface flaws in an auto's interior? (b) if 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws? (c) if 10 cars are sold to a rental company, what is the probability that at most 1 car has any surface flaws? round your answers to four decimal places (e. g. 98.7654).

a) 0.4065

b) 0.000126

c) 0.001921

Step-by-step explanation:

Given data:

Poisson distribution mean = 0.06

Amount of plastic panel = 10 square panel

Probability mass function given by Poisson distribution is

      x: 0,1,2,......

where is parameter

here lambda is 0.06 per  square ft

a)  from Poisson distribution

B) PROBABILITY OF NO SURFACE FLAWS IN CAR

N = 10

p = 1 - 0.406 = 0.5934

q = 0.4065

             = 0.000126

c) probability of 1 car flaw

                  = 0.001921

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.