Which polynomials are in standard form?

x2y3 + y + 3xy2

– 5a3 + 12a2b – 15ab2 + b3

4xy + 2x2y2 + xy3

7x4 + 4x3y – 3x2y2 – y4

14b3 + ab3 – 6ab + 8ab2

3a4 + 4a3b – 6a2b2 – 4ab3 – b4

The Answers Are B. D. and F.

Step-by-step explanation:

Because watermelons are bigger than mice. :)

Option 2,4,6 are correct.

Step-by-step explanation:

To find : Which polynomials are in standard form?

Solution :

A polynomial is in standard form when its term of highest degree is first, its term of 2nd highest is 2nd and so on.

Now we check all,

1)

As y degree is 1 so it goes to last.

No, it is not standard form.

2)

Yes, it is standard form as all of them degree is 3.

3)

As first term degree is 2 and last two term degree is 4 so first term goes to last.

No, it is not standard form.

4)

Yes, it is standard form as all of them degree is 4.

5)

As third term degree is 2 and last term degree is 3 so third term goes to last.

No, it is not standard form.

6)

Yes, it is standard form as all of them degree is 4.

Therefore, option 2,4,6 are correct.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

my guess would be b and d, but i didn’t actually get out the pen and paper. lol