C. find a parametrization for the line segment with endpoints (-1, 3) and (3, -2).

x(t) = -1 + 4t

y (t) = 3 - 5t

Step-by-step explanation:

The end points of the line segment are (-1, 3) and (3, -2).

Let a = (-1,3) and b = (3,-2)

Now, find the value of (b-a)

(b-a) = ((3+1), (-2-3))

b-a = (4, -5)

Therefore, the parametrization of the given line segment is

r(t) = a + (b-a)t

r(t) = (-1,3) +(4,-5)t

r(t) = (-1+4t, 3-5t)

We can rewrite this as

x(t) = -1 + 4t

y (t) = 3 - 5t

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17