Asurvey of athletes at a high school is conducted, and the following facts are discovered: 40% of the athletes are football players, 59% are basketball players, and 13% of the athletes play both football and basketball. an athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player? probability = % ( enter your answer as a percent)

86%

Step-by-step explanation:

Let

A= Football player

B= Basket ball player

Football players=40%

Basketball players=59%

Both football and basket ball players=13%

Total percent=100%

The probability that athlete is a football player=P(A)=

The probability that athlete is a basketball player=P(B)=

The probability that athlete is both basket ball player and  football player=

We have to find the probability that athlete is either a football player or a basketball player.

It means we have to find

We know that

86%

Hence, the probability that the athlete is either a football player or a basketball player=86%

the answer is $42.96

step-by-step explanation:

answer:

1.14285714286

step-by-step explanation:

divide 40 into 35 and you will get your answer